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Discussion: Conditional Probability

Discussion: Conditional Probability

Example
Let’s look at a standard deck of 52 cards.
What is the probability of getting 2 kings assuming that the first one is not replaced?
4/52 * 3/51 = 1/13*1/17= 1/221
What is the probability of getting 2 kings assuming that the first one is replaced?
4/52 * 4/52 = 1/13 * 1/13 = 1/169
Instructions
Now for your main post do a similar problem using with replacement and without replacement. You can use a card problem as long as it is not 2 kings. Try your best to be original. Do not solve your own problems. Leave them for your classmates to work.

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